Use this free online calculator to convert Feet [Pre 1963 Canada] to Bohr instantly. This all length conversions conversion tool provides accurate results for all your measurement needs.

Quick Reference

1 Feet [Pre 1963 Canada] = 6141577535.05 Bohr

1 Bohr = 1.628e-10 Feet [Pre 1963 Canada]

Feet [Pre 1963 Canada] to Bohr Conversion Formula

To convert Feet [Pre 1963 Canada] to Bohr, multiply by 6141577535.05.

Bohr = Feet [Pre 1963 Canada] × 6141577535.05

Feet [Pre 1963 Canada] = Bohr × 1.628e-10

To convert Bohr back to Feet [Pre 1963 Canada], divide by 6141577535.05 (or multiply by 1.628e-10).

About These Units

About Feet [Pre 1963 Canada]

A foot (plural: feet) is a non-SI unit of distance or length, measuring around a third of a metre. There are twelve inches in one foot and three feet in one yard.

About Bohr

The Bohr is a unit of distance commonly used in particle physics. It was named after the Danish physicist Niels Bohr (1885-1962), who explained the structure of atoms in a famous paper in 1913. The Bohr radius represents the mean distance between the proton and the electron in an unexcited hydrogen atom. It equals about 52.918 picometers (pm), or 52.918 x 10e-12 meter.

Feet [Pre 1963 Canada] to Bohr Conversion Table

Feet [Pre 1963 Canada]	Bohr	Bohr	Feet [Pre 1963 Canada]
0.1	614157753.51	0.1	1.628e-11
0.5	3070788767.53	0.5	8.141e-11
1	6141577535.05	1	1.628e-10
2	12283155070.11	2	3.256e-10
5	30707887675.27	5	8.141e-10
10	61415775350.54	10	1.628e-9
20	122831550701.08	20	3.256e-9
25	153539438376.36	25	4.071e-9
50	307078876752.71	50	8.141e-9
100	614157753505.42	100	1.628e-8
250	1535394383763.56	250	4.071e-8
500	3070788767527.12	500	8.141e-8
1000	6141577535054.24	1000	1.628e-7

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