Use this free online calculator to convert Bohr to Feet [Pre 1963 Canada] instantly. This all length conversions conversion tool provides accurate results for all your measurement needs.

Quick Reference

1 Bohr = 1.628e-10 Feet [Pre 1963 Canada]

1 Feet [Pre 1963 Canada] = 6141577535.05 Bohr

Bohr to Feet [Pre 1963 Canada] Conversion Formula

To convert Bohr to Feet [Pre 1963 Canada], multiply by 1.628e-10.

Feet [Pre 1963 Canada] = Bohr × 1.628e-10

Bohr = Feet [Pre 1963 Canada] × 6141577535.05

To convert Feet [Pre 1963 Canada] back to Bohr, divide by 1.628e-10 (or multiply by 6141577535.05).

About These Units

About Bohr

The Bohr is a unit of distance commonly used in particle physics. It was named after the Danish physicist Niels Bohr (1885-1962), who explained the structure of atoms in a famous paper in 1913. The Bohr radius represents the mean distance between the proton and the electron in an unexcited hydrogen atom. It equals about 52.918 picometers (pm), or 52.918 x 10e-12 meter.

About Feet [Pre 1963 Canada]

A foot (plural: feet) is a non-SI unit of distance or length, measuring around a third of a metre. There are twelve inches in one foot and three feet in one yard.

Bohr to Feet [Pre 1963 Canada] Conversion Table

Bohr	Feet [Pre 1963 Canada]	Feet [Pre 1963 Canada]	Bohr
0.1	1.628e-11	0.1	614157753.51
0.5	8.141e-11	0.5	3070788767.53
1	1.628e-10	1	6141577535.05
2	3.256e-10	2	12283155070.11
5	8.141e-10	5	30707887675.27
10	1.628e-9	10	61415775350.54
20	3.256e-9	20	122831550701.08
25	4.071e-9	25	153539438376.36
50	8.141e-9	50	307078876752.71
100	1.628e-8	100	614157753505.42
250	4.071e-8	250	1535394383763.56
500	8.141e-8	500	3070788767527.12
1000	1.628e-7	1000	6141577535054.24

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